A 60.0 kg person running at an initial speed of +3.40 m/s jumps onto a 120 kg ca

Question

A 60.0 kg person running at an initial speed of +3.40 m/s jumps onto a 120 kg cart that is initially at rest. The person slides on the cart's top surface and finally comes to rest relative to the cart. The coefficient of kinetic friction between the person and the cart is 0.445. Friction between the cart and the ground can be neglected. (e) Determine the displacement of the person relative to the ground while he is sliding on the cart.

For this question, do i have to add the displacement of the person and the cart?

Explanation / Answer

Displacement of person relative to ground = displacement of person relative to cart + displacement of cart relative to ground

I am off to bed soon but here are the hints: 1) draw a FBD of the man when he is on the cart. From that, you determine his acceleration and you will be able to determine how far he slides relative to the cart. (you know vinitial and vfinal and can solve for distance) 2) Draw a FBD of the cart. you will again be able to determine the acceleration of the cart but it will be less than in 1). From this FBD, you will be able to determine how far the cart moves relative to the ground. (you will know vinitial and vfinal and can solve for distance) 3) Adding 1) and 2) should give you the answer you seek.

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