A uniform steel beam has a mass of 610kg . On it is resting half of an identical

Question

A uniform steel beam has a mass of 610kg . On it is resting half of an identical beam, as shown in (Figure 1) .

Part A

Determine the vertical support force at A.

Express your answer to two significant figures and include the appropriate units.

Part B

Determine the vertical support force at B.

Express your answer to two significant figures and include the appropriate units

PLEASE EXPLAIN YOUR ANSWERS STEP BY STEP> THANKS !!!

A uniform steel beam has a mass of 610kg . On it is resting half of an identical beam, as shown in (Figure 1) . Part A Determine the vertical support force at A. Express your answer to two significant figures and include the appropriate units. Part B Determine the vertical support force at B. Express your answer to two significant figures and include the appropriate units PLEASE EXPLAIN YOUR ANSWERS STEP BY STEP> THANKS !!!

Explanation / Answer

net torque about B =

Fa*L = M*g*L/2 + (M/2)*g*3L/4

Fa = 3Mg/4 = (3*610*9.8)/4

Fa = (7/8)*M*g = (7/8)*610*9.8 = 5230.75 N

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part B

Fy net = 0

Fa + Fb - M*g - (M/2)*g = 0

(7/8)*M*g + Fb - M*g - (M/2)*g = 0

Fb = (5/8)*M*g = (5*610*9.8)/8 = 3736.25 N

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