A hydrogen atom emits a photon that has momentum 0.6592e-27 kg*m/s. This photon

Question

A hydrogen atom emits a photon that has momentum 0.6592e-27 kg*m/s. This photon is emitted because the electron in the atom falls from a higher energy level into the n = 3 level. What is the quantum number of the level from which the electron falls? Use values of h = 6.626e-34 Js, c = 2.998e8 m/s, and e = 1.602e-19 C.

A hydrogen atom emits a photon that has momentum 0.6592e-27 kg*m/s. This photon is emitted because the electron in the atom falls from a higher energy level into the n = 3 level. What is the quantum number of the level from which the electron falls? Use values of h = 6.626e-34 JA hat?s, c = 2.998e8 m/s, and e = 1.602e-19 C

Explanation / Answer

we are given momentum

and so we can find change in energy

and then

using formula

E2-E1=-13.6(1/n12-1/n22)

we know n2=3 ,

we can fing n1

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