(a) Find the water\'s speed in the wider pipe. (m/s) Note that there is no chang

Question

(a) Find the water's speed in the wider pipe. (m/s)

Note that there is no change in height in this exercise. Both parts of the pipe are at the same level.

(b) Find the water's speed in the narrower pipe.
m/s

Water flowing in a horizontal pipe is at a pressure of 1.20 x 10^5 Pa. (a) Find the water's speed in the wider pipe. (m/s) Note that there is no change in height in this exercise. Both parts of the pipe are at the same level. (b) Find the water's speed in the narrower pipe. m/s x 10^5 Pa at a point where its cross-sectional area is 3.50 m^2. When the pipe narrows to 0.400 m^2, the pressure drops to 1.16

Explanation / Answer

FROM EQUATION OF CONTINUTY

A1*V1= A2*V2....

3.5*V1 = 0.4*V2...
V1/V2 = 0.4/3.5 = 0.114......(1)...

from bernoullies theorem...

2P1+ (rho*V1^2) = 2P2 + (rho*V2^2)...

rho(V2^2-V1^2) = 2(P1-P2)...

V2^2-V1^2 = 2(1.2-1.16)*10^5/1000 = 8....(2)..
but from (1)

V1= 0.114*V2...

V2^2-(0.114*V2)^2 = 8...

V2 = sqrt(8/0.987) = 2.846 m/sec..
V1 = 0.114*2.846 = 0.324 m/sec

answer for A) V1 = 0.324 m/sec..

answer for B) V2 = 2.846 m/sec

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