A light spring of force constant k = 158 N/m rests vertically on the bottom of a

Question

A light spring of force constant k = 158 N/m rests vertically on the bottom of a large beaker of water (Figure a). A 5.74-kg block of wood (density = 650 kg/m3) is connected to the spring, and the block-spring system is allowed to come to static equilibrium (Figure b). What is the elongation ?L of the spring?
cm

A light spring of force constant k = 158 N/m rests vertically on the bottom of a large beaker of water (Figure a). A 5.74-kg block of wood (density = 650 kg/m3) is connected to the spring, and the block-spring system is allowed to come to static equilibrium (Figure b). What is the elongation ?L of the spring? cm

Explanation / Answer

Fb + Fy = Fg

dwater*V*g - k*dL = m*g

dwater * m/dwood *g - k * dL = m*g

(1000/650)*5.74*9.8 - (158*dL) = (5.74*9.8)

dL = 0.192 m

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