A box of weight w=2.0N accelerates down a rough plane that is inclined at an ang

Question

A box of weight w=2.0N accelerates down a rough plane that is inclined at an angle 30 degrees above the horizontal, as shown (Figure 6) . The normal force acting on the box has a magnitude n=1.7N, the coefficient of kinetic friction between the box and the plane is k=0.30, and the displacement of the box is 1.8 m down the inclined plane.

What is the work Ww done on the box by the weight of the box?

A box of weight w=2.0N accelerates down a rough plane that is inclined at an angle 30 degrees above the horizontal, as shown (Figure 6) . The normal force acting on the box has a magnitude n=1.7N, the coefficient of kinetic friction between the box and the plane is AA1/4k=0.30, and the displacement of the box is 1.8 m down the inclined plane. What is the work Ww done on the box by the weight of the box?

Explanation / Answer

Vertical distance = 1.8 sin 30 = 0.90 m
W = 2.0 N * 0.90 m = 1.80J

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.