A wooden block with mass 1.55kg is placed against a compressed spring at the bot

Question

A wooden block with mass 1.55kg is placed against a compressed spring at the bottom of a slope inclined at an angle of 31.0? (point A). When the spring is released, it projects the block up the incline. At point B, a distance of 6.05m up the incline from A, the block is moving up the incline at a speed of 6.30m/s and is no longer in contact with the spring. The coefficient of kinetic friction between the block and incline is ?k = 0.50. The mass of the spring is negligible.

Part A

Calculate the amount of potential energy that was initially stored in the spring.

Take free fall acceleration to be 9.80m/s2 .

PLZ GIVE ME SPESIFIC STEPS! I REALLY DO NOT KNOW HOW TO SOLVE THIS!

Explanation / Answer

form work energy theorem,

work done by friction + work done by gravity = (final K.e + P.E.) - initial (K.E. + P.E.)

- 0.50 x 1.55 x 9.8 x cos31 x 6.05 - 1.55 x 9.8 x sin31 x 6.05 = 1.55 x 6.30^2 /2 - stored P.E.

stored P.E. = 117.89 J

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