A wooden block is cut into two pieces, one with three timesthe mass of the other
ID: 1721905 • Letter: A
Question
A wooden block is cut into two pieces, one with three timesthe mass of the other. A tiny depression is made in both faces ofthe cut, so that a firecraker can be placed in it with the blockreassembled. The reassembled block is set on a rough-surfaced tableand the fuse is lit.when the firecracker explodes, the two blocksseparate and slide apart. the small pieces slides a distance "d",the big pieces slides a distance "D". what is the ratio of d/D ofdistance each block travles? (ignore firctional forces form the table during theexplosion) A wooden block is cut into two pieces, one with three timesthe mass of the other. A tiny depression is made in both faces ofthe cut, so that a firecraker can be placed in it with the blockreassembled. The reassembled block is set on a rough-surfaced tableand the fuse is lit.when the firecracker explodes, the two blocksseparate and slide apart. the small pieces slides a distance "d",the big pieces slides a distance "D". what is the ratio of d/D ofdistance each block travles? (ignore firctional forces form the table during theexplosion)Explanation / Answer
The first response is incorrect. . By conservation of momentum... . momentum of small piece = momentum of large piece . m v = M V where I have used v and V for thespeeds of the blocks . divide both sides byMV... mv / MV = 1 or m v / (3m) V = 1 . so... v / V = 3 . Now... they are both stopped by friction after traveling adistance d and D respectively. . The work done by friction on each must equal the kineticenergy of each block. So for the small block... . (1/2) m v2 = m gd and the largeblock (1/2) M V2 = M g D . We can simplify each of these . v2 = 2 gd and V2 = 2 g D . Now... take the ratio of these two equations: . v2 / V2 = 2 d g/ 2 g D . Simplify: ( v/ V)2 = d / D . But we already know the ratio of the speed is 3 (from above)... . So... d / D = 32 d / D = 9Related Questions
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