A(n) 250 g block is pushed by an external force against a spring with spring con

Question

A(n) 250 g block is pushed by an external force against a spring with spring constant of 1120 N/m until the spring is compressed by 16.5 cm from its uncompressed length. The compressed spring and block rests at the bottom of an incline of angle = 27.0°. Note that the spring lies along the surface of the ramp (see Figure). Assume that the ramp is frictionless. Now, the external force is rapidly removed so that the compressed spring can push up the mass. How far up the ramp (i.e., the length along the ramp) will the block move (measured from the uncompressed end of the spring) before reversing direction and sliding back? Remember, the block is not attached to the spring. Answer in units of m. Use 9.80 m/s2 for g.

Explanation / Answer

0.5*1120*0.165*0.165 = 0.25*9.8*sin27*d

d = 13.7 m along incline

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.