A 15-kg shell is traveling horizontally to the right at 20m/s relative to the gr

Question

A 15-kg shell is traveling horizontally to the right at 20m/s relative to the ground when it explodes into two fragments, one of the mass 6kg and the other mass of 9kg. The lighter fragment goes directly forward, and the explosion releases 1.5*e3 J of mechanical energy to the fragments. Find the magnitude and direction of the velocity of the heavier fragment relative to the ground just after the explosion. Ignore the effects of any ejected gasses. A 15-kg shell is traveling horizontally to the right at 20m/s relative to the ground when it explodes into two fragments, one of the mass 6kg and the other mass of 9kg. The lighter fragment goes directly forward, and the explosion releases 1.5*e3 J of mechanical energy to the fragments. Find the magnitude and direction of the velocity of the heavier fragment relative to the ground just after the explosion. Ignore the effects of any ejected gasses.

Explanation / Answer

final velocity of 9kg is v1 and of 6kg is v2 then.

momentum will be conserved.

15 x 20 = 6v2 - 9v1

v2 = 50 + 1.5v1

and form enery conservation,

[9v1^2 /2 + 6v2^2 /2 ] - 15 x 20^2 /2 = 1.5x 10^3   

putiing value of v2.

[9v1^2 /2 + 6( 50 + 1.5v1 )^2 /2 ] - 15 x 20^2 /2 = 1.5x 10^3   

solve and get value of v1.

hope this will help u

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