It is desired to construct a solenoid that will have a resistance of 5.80 * 10^-

Question

It is desired to construct a solenoid that will have a resistance of 5.80 * 10^-8 ? A . m) (a) the number of turns of wire needed to build the solenoid (b) the length the solenoid should have Omega (at 20 degree C) and produce a magnetic field of 4.00 ? 10^-2 T at its center when it carries a current of 4.80A. The solenoid is to be constructed from copper wire having a diameter of 0.500 mm. If the radius of the solenoid is to be 1.00 cm, determine the following. (The resistivity of copper at 20 degree C is 1.7

Explanation / Answer

B due to solonoid is B = uoNi/l

so N = No. of tunrs = B* L/(uoi)

N/L = 0.04/(4pie-7 * 4.8)

N/L =   6634.82 turns/m

total length of the wire is R = rho*L/A

so L = RA/rho

L = 5.8 * 3.14* 0.25*0.25 e-6/(1.7e-8)

L = 66.95 m

so No. of turns N = 6634.82* 66.95 =444201 turns

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