A 1000- kg car collides with a 1300- kg car that was initially at rest at the or

Question

A 1000- kg car collides with a 1300- kg car that was initially at rest at the origin of an x-y coordinate system. After the collision, the lighter car moves at 20.0 km/h in a direction of 25 o with respect to the positive x axis. The heavier car moves at 23 km/h at -44 o with respect to the positive x axis.

A 1000- kg car collides with a 1300- kg car that was initially at rest at the origin of an x-y coordinate system. After the collision, the lighter car moves at 20.0 km/h in a direction of 25 o with respect to the positive x axis. The heavier car moves at 23 km/h at -44 o with respect to the positive x axis.

Explanation / Answer

sum momentum in the x

1000*x = 20*1000*cos(25 degrees) + 23*1300*cos(44 degrees)

x=39.63 km/h

sum in the y

1000*y = 20*1000*sin(25 degrees) + 23*1300*cos(-44 degrees)

y=29.96 km/hr

v = sqrt(39.63^2 + 29.96^2)= 49.68 km/hr

direction = arctan(29.96/39.63)= 37.1 degrees

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