An AM radio transmitter broadcasts 46.0 kW of power uniformly in all directions.

Question

An AM radio transmitter broadcasts 46.0 kW of power uniformly in all directions. Assuming all of the radio waves that strike the ground are completely absorbed, and that there is no absorption by the atmosphere or other objects, what is the intensity 25.0 km away? (Hint: Half the power will be spread over the area of a hemisphere.)
(in W/m^2) 5.8610-6 W/m^2

What is the maximum electric field strength at this distance?
(in mV/m)

i have problem with part of the question i can't which formula to use in this part is any one know how to solve it?

You are correct.
Your receipt no. is 169-1437 An AM radio transmitter broadcasts 46.0 kW of power uniformly in all directions. Assuming all of the radio waves that strike the ground are completely absorbed, and that there is no absorption by the atmosphere or other objects, what is the intensity 25.0 km away? (Hint: Half the power will be spread over the area of a hemisphere.) (in W/m^2) 5.86½10^-6 W/m^2 You are correct. Your receipt no. is 169-1437 What is the maximum electric field strength at this distance? (in mV/m) i have problem with part of the question i can't which formula to use in this part is any one know how to solve it?

Explanation / Answer

Intentsity I = power/area = Emax^2/2uoC

I = 46000/(4pi* 25000*25000)

I =5.86*10^-6 W/m^2

so Emax^2 = I * 2uoC

Emax^2 = 5.86*10^-6 * 2* 4pie-7 * 3e8

Emax = 66.45 mV/m

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