243 PM LON-CAPA a loncapa.gwu.edu Michelle charged Particle in B-Fi... Awkward (

Question

243 PM LON-CAPA a loncapa.gwu.edu Michelle charged Particle in B-Fi... Awkward (Season 4) 12 IEp IFinals Main Garcia v (student) l Menu Contents Phy 212 FA2014 Grades Course Contents Messages Courses Help Hws 4 O Tmer Notes d Evaluate Feedback Print magnetic field as indicated. will A positively charged particle is moving with a velocityvin a large homogene right into the paper. O down. left. O out of the paper. O not at all. Submit Answer Tries 0/3 The shape of its trajectory will be circular, counter-clockwise. O parabolic, curving down O straight, speeding up. O parabolic, curving into the paper. O straight, continuing at same speed. O parabolic, curving out of the paper O circular, clockwise. parabolic, curving up. O straight, slowing down. Submit Answer Tries o/3 If the field is of the particle is 43.10 kg, its initial speed 7.2 m/s, and its charge 3 uc, what is 4 m T, the mass the magnitude of its acceleration? (in m/sn2) Submit Answer Tries o/10 What is the speed of the particle 2.4 seconds later? (in m/s) Submit Answer Tries o/10 My general preferences on what is marked as NEw Threaded View Chronological View -other VIews lawira Appiah Beply (Mon Sep 29 o6:30:24 pm 2014 (EDT)

Explanation / Answer

First part: Force will be upwards

Second part: Parabolic, curving up

Third part: Using the equations Fb = qvb sin(theta), F=ma

Fb = (3*10^-6)*(7.2)*(4*10^-3)*1 = 86.4*10^-9 N

a = (86.4*10^-9)/(43*10^-9) = 2.01 m/s^2

Fourth part: v = at, pythagorean theorem

Vy = 2.01*2.4

Vy = 4.82m/s    Vx = 7.2m/s

V^2 = Vy^2 + Vx^2

V^2 = 23.27 + 51.84

V^2 = 75.11

V = 8.67 m/s

Cheers.

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