4. Two forces, ?F1 and ?F2, are as shown in the diagram below. They are exerted

Question

4. Two forces, ?F1 and ?F2, are as shown in the diagram below. They are exerted on an object at the angles ?1 = 47? and ?2 = 12?, and have magnitudes given by F1 = 3.4 N and F2 = 4.7 N (the symbol N stands for newtons, the MKS units for force; we will get to this in a couple of chapters). What are the x- and y-components of the two forces?

5. The net force acting on the object in the problem above is simply the vector sum of the individual forces acting on it. In this case,?Fnet = ?F1 + ?F2

What are the magnitude and direction of the net force acting on the object?

Please show work

4. Two forces, ?F1 and ?F2, are as shown in the diagram below. They are exerted on an object at the angles ?1 = 47? and ?2 = 12?, and have magnitudes given by F1 = 3.4 N and F2 = 4.7 N (the symbol N stands for newtons, the MKS units for force; we will get to this in a couple of chapters). What are the x- and y-components of the two forces? 5. The net force acting on the object in the problem above is simply the vector sum of the individual forces acting on it. In this case,?Fnet = ?F1 + ?F2 What are the magnitude and direction of the net force acting on the object?

Explanation / Answer

F1x = F*cos47 = 2.32 N.............F1y = 3.4*sin47 =2.48

F2x = -4.7*sin12 = - 0.977N.......F2y = -4.7*cos12 = -4.59 N

Fx = F1x + F2x = 1.343

Fy = 2.48-4.59 = -2.11 N

F = sqrt(Fx^2+Fy^2) = 2.501 N

direction = tan^-1(Fy/Fx) = 57.52 with +x axis

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