The electron gun is an old TV picture tube accelerates electrons between two par

Question

The electron gun is an old TV picture tube accelerates electrons between two parallel plates 1.5cm apart with a 21kV potential difference between them. The electron enters through a small hole in the negative plate, accelerate, then exit through a small hole in the positive plate. Assume that the holes are small enough not to affect the electric field or potential. Part A What is the electric field strength between the plates? Express your answers to two significant figures and include the appropriate units. E = Value Units Part B With what speed does an electron exit the electron gun if its entry speed is close to zero? Express your answer to two significant figures and include the appropriate units. Vexit = Value Units

Explanation / Answer

EF E = V/d

E = 21000/(0.015)

E = 1.4 *10^6 N/C
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B .

0.5 mv^2 = eV

v^2 = 1.6e-19 * 21000*2/(9.11e-31)

V = 8.58 *10^7 m/s

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