As a helicopter carrying a crate takes off, its vertical position (as well as th

Question

As a helicopter carrying a crate takes off, its vertical position (as well as the crates) is given as: y(t) = At 3 , where A is a constant and t is time with t = 0 corresponding to when it leaves the ground. When the helicopter reaches a height of h = 15.0 m the crate is released from the underside of the aircraft. From the time the crate leaves the helicopter t o the time it hits the ground, 2 .5 0 seconds pass. Calculate A

I need the drawing steps too. if someone can do that that will be great.

Explanation / Answer

h = A*t^3

15 = A*2.5^3

A = 0.435 m/s^3

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