You toss a racquetball directly upward and then catch it at the same height you

Question

You toss a racquetball directly upward and then catch it at the same height you released it 2.06 s late (a) What is the acceleration of the ball while it is moving upward? magnitude direction m/s -Select (b) What is the acceleration of the ball while it is moving downward? magnitude direction m/s -Select (c) What is the acceleration of the ball while it is at its maximum height? magnitude direction m/s -Select (d) What is the velocity of the ball when it reaches its maximum height? magnitude direction m/s -Select (e) What is the initial velocity of the ball? magnitude direction m/s -Select (f) What is the maximum height that the ball reaches?

Explanation / Answer

a) g = 9.8 m/s^2 (downward)

b) g = 9.8 m/s^2 (downward)

c) g = 9.8 m/s^2 (downward)

d) V = 0

e) Time of flight, T = 2*u/g

==> u = g*T/2

= 9.8*2.06/2

= 10.094 m/s (upward)

f) H = u^2/(2*g)

= 10.094^2/(2*9.8)

= 5.2 m

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