You toss a racquetball directly upward and then catch it at the same height you

ID: 1310737 • Letter: Y

Question

You toss a racquetball directly upward and then catch it at the same height you released it 2.10 s later. Assume air resistance is negligible.

(a) What is the acceleration of the ball while it is moving upward?

*I got: 9.8 m/s^2, downward

(b) What is the acceleration of the ball while it is moving downward?

*I got: 9.8 m/s^2, downward

(d) What is the velocity of the ball when it reaches its maximum height?

*I got: 0 m/s

(e) What is the initial velocity of the ball?

*I got: 10.8 m/s, upward

(f) What is the maximum height that the ball reaches?

= ??? m

Time of flight=2.1 sec

So 2u/g=2.1 sec

u=2.1(g)/2

=2.1(9.81)/2

=10.3005 m/s

Maximium Height reached by the ball=u^2/2g

=(10.3005)^2/2(9.81)

=5.4077 m

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