A ray of light strikes a flat, 2.00-cm-thick block of glass (n = 1.73) at an ang

Question

A ray of light strikes a flat, 2.00-cm-thick block of glass (n = 1.73) at an angle of Theta = 15.7 degree with respect to the normal (see figure below). Find the angle of refraction at the top surface and the angle of incidence at the bottom surface. Find the refracted angle at the bottom surface. Find the lateral distance d by which the light beam is shifted. Your response is within 10% of the correct value. This may be due to roundoff error, or you could have a mistake in your calculation. Carry out all intermediate results to at least four-digit accuracy to minimize roundoff error. cm Calculate the speed of light in the glass. Calculate the time required for the light to pass through the glass block.

Explanation / Answer

for Lateral displacement d, we use the formula

d= t * (sin(i-r)/cos r)

where t is the thickness through which light travels(2cm in this case) and i = angle of incidence and r = angle of refraction. so,

d = 2 * (sin(15.7-8.99)/ cos 8.99)

d = 2 * (0.11684/.98771)

d= 2 * .11829

d= 0.23658 cm

For the time it takes, we take the component of velocity in the direction along its thickness and then determine the time using t = s/v where t is the time, v is the velocity and s is the distance travelled.

t = 2/1.734e8cos 8.99 (cos 8.99 as velocity makes angle equal to angle of refraction in the direction of normal or along the thichness of glass)

t= 1.1677e-10 sec (keep the correct unit of velocity i.e in cm/sec because distance traversed is in cm)

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