A ray of light strikes a flat, 2.00-cm-thick block of glass (n = 1.69) at an ang

Question

A ray of light strikes a flat, 2.00-cm-thick block of glass (n = 1.69) at an angle of Theta = 31.6 degree with respect to the normal (see figure below). (a) Find the angle of refraction at the top surface and the angle of incidence at the bottom surface. Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. degree (b) Find the refracted angle at the bottom surface. degree (c) Find the lateral distance d by which the light beam is shifted. cm (d) Calculate the speed of light in the glass. m/s (e) Calculate the time required for the light to pass through the glass block. s

Explanation / Answer

a) n = sin i / sin r

or, sin r = sin i/n = 0.31

or, r =18.06 degrees.

b) The refracted angle at the bottom surface will be same as at incident angle at the top surface and thus is equal to 31.6 degrees.

c) d = t*sin(i-r)/cosr = 2*sin(31.6-18.06)/cos 18.06 = 0.5 cm

d) Speed of light in glass = speed of light in vacuum/ n = 1.78*10^8 m/s

e) Time required = (2/cosr) / speed = 1.182 * 10^-10 seconds

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