A scuba tank when fully charged has a pressure of 190atm at 23 degree C. The vol

Question

A scuba tank when fully charged has a pressure of 190atm at 23 degree C. The volume of the tank is 11.6L. What would the volume of the air be at 1.00atm and at the same temperature? Before entering the water, a person consumes 2.0L of air in each breath, and breathes 13 times a minute. At this rate, how long would the tank last? At a depth of 26m in sea water (where the pressure has increased by 2.6x105Pa) at a temperature of 13 degree C, how long would the same tank last assuming the breathing rate does not change?

Explanation / Answer

3) a) since P V = n R T

if T is constant

P V = P V

190*11.6 =1*V

V = 190*11.6= 2204 L

b)

2204/(2*13)= 84.8 minutes

c) now

PV/T = P V/T

190*1.013E5*11.6/(23+273.15) = (1.013E5 + 2.6E5)*V/(13+273.15)

V= 597.08 L

so 597.08/(2*13)=22.96 minutes

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