Two go-karts race around a course that has concentric circular tracks. The radiu
ID: 1271356 • Letter: T
Question
Two go-karts race around a course that has concentric circular tracks. The radius of the inner track is 15.0 m, and the radius of the outer track is 19.0 m. The go-karts start from rest at the same angular position and time, and move at the same constant angular acceleration. The race ends in a tie after one complete lap, which takes 21.5 seconds. (a) What is the common angular acceleration of the carts? (b) What is the tangential acceleration of the inner cart? (c) What is the tangential acceleration of the outer cart?
I got the answer below but keep getting it wrong! can someone please help!?
Angular acceleration = (Increase of angular velocity)
Explanation / Answer
a) 2pi = 0.5*a*t^2
t = time of race, a =angular acceleration
a = 0.0271rad/sec^2
b) tangential acceleration = radius*angular acceleration
= .0271*15 = .407m/sec^2
c)outer cart = .0271*19 = 0.5149m/sec^2
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