Two genes are located on the same chromosome and are known to be 12 mu apart. An

Question

Two genes are located on the same chromosome and are known to be 12 mu apart. An AABB individual is crossed to an aabb individual to produce AaBb offspring. The AaBb offspring are then crossed to aabb individuals.   If this cross produces 1,000 offspring, what are the predicted numbers of offspring of each of the four genotypes: AaBb, Aabb, aaBb and aabb? THIS IS WHAT I THINK THE ANSWER IS.

100-12=88 /2 = 44

12/2 = 6

AaBb: .44*1000= 440 progeny

Aabb: .06*1000= 60 progeny

aaBb: .06*1000= 60 progeny

aabb: .44*1000= 440 progeny

What would be the predicted numbers of offspring of these four genotypes if the parental generation had been AAbb and aaBB instead of AABB and aabb? MY ANSWER: Same resulting progeny

Explanation / Answer

Part A- The predicted number would be 250 each as the ratio of the genotypes AaBb: Aabb: aaBb : aabb is coming out to be 1:1:1:1.

Part B- Cross between AAbb and aaBB will give the same F1 offspring - AaBb. After crossing with aabb, it will form the same ratio of offsprings as mentioned above.

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