Two genes interact to produce various phenotypic ratios among F2 progeny of a di
ID: 51715 • Letter: T
Question
Two genes interact to produce various phenotypic ratios among F2 progeny of a dihybrid cross. Design a different pathway explaining each of the F2 ratios below, using hypothetical genes R and T and assuming that the dominant allele at each locus catalyzes a different reaction or performs an action leading to pigment production. The recessive allele at each locus is null (loss-of-function). Begin each pathway with a colorless precursor that produces a white or albino phenotype if it is unmodified. The ratios are for F2 progeny produced by crossing wild-type F1 organisms with the genotype RrTt.
9/16 Dark Blue 6/16 light blue 1/16 white
A) At least one copy of each dominant allele results in dark blue, at least one copy of either dominant allele produces light blue, and the absence of both dominant allele produces white. B) If both dominant alleles are present, the result is dark blue. At least one copy of one specific dominant allele is required for light blue. If that dominant allele is not present, the result is white, regardless of whether the other dominant allele is present. C) At least one copy of both dominant alleles results in dark blue; at least one copy of one of the dominant alleles also results in dark blue, but at least one copy of the other dominant allele produces light blue; and the absence of either dominant allele produces white.Explanation / Answer
ANSWER
The statement A is correct.
At least one copy of each dominant allele results in dark blue, at least one copy of either dominant allele produces light blue, and the absence of both dominant alleles produces white
Explanation:
The present cross is a type of epistasis namely Duplicate genes with cumulative effect.
Duplicate genes with cumulative effect: Certain phenotypic traits depend on the dominant alleles of two gene loci. When dominant is present it will show its phenotype. The ratio will be 9: 6: 1. Complete dominance at both gene pairs, interaction between both dominance to give new phenotypes.
From the data given
Gene pair R Blue dominant over white or albino.
Gene pair T Blue dominant over white or albino.
Interaction at RT when present together, forms a Dark blue coloured progeny.
RRrr X TTtt
Blue coloured Blue coloured
Gametes produced are Rr and Tt
The progeny produced in F1 generation are RrTt – Dark Blue
If we crossed F1 progeny with RrTt then as follows
RrTt X RrTt
Then F2 progeny as follows
RT
Rt
rT
rt
RT
RRTT, Dark blue
RRTt, Dark blue
RrTT, Dark blue
RrTt, Dark blue
Rt
RRTt, Dark blue
RRtt, Light blue
RrTt, Dark blue
Rrtt, Light blue
rT
RrTT, Dark blue
RrTt, Dark blue
rrTT Light blue
rrTt Light blue
rt
RrTt, Dark blue
Rrtt, Light Blue
rrTt , Light blue
rrtt, white
Dark Blue-9/16: 6/16 Light blue: 1/16white
At least one copy of each dominant allele in present in Dark blue.
At least one copy of either of the dominant allele is present in Light blue.
Both the dominant alleles are completly absent in White.
RT
Rt
rT
rt
RT
RRTT, Dark blue
RRTt, Dark blue
RrTT, Dark blue
RrTt, Dark blue
Rt
RRTt, Dark blue
RRtt, Light blue
RrTt, Dark blue
Rrtt, Light blue
rT
RrTT, Dark blue
RrTt, Dark blue
rrTT Light blue
rrTt Light blue
rt
RrTt, Dark blue
Rrtt, Light Blue
rrTt , Light blue
rrtt, white
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