Two negative charges, Q = -25 C are placed on the x-axis at x = +0.5 m and x = -

ID: 1266869 • Letter: T

Question

Two negative charges, Q = -25 C are placed on the x-axis at x = +0.5 m and x = -0.5 m.

A)How much energy does it take to assemble these two charges?

B) You place an unknown charge on the y-axis at y = 1 m and find that the electric potential is 0 V at the origin. What is the unknown charge?

C)If you place a -4 C charge at the origin, what is the x-component of the force on it from the other three charges?

D)If you place a -4 C charge at the origin, what is the y-component of the force on it from the other three charges?

Steps and actual final values if possible please, thank you

a) E = k q Q/r = 9.0E9*25.0E-6^2/1= 5.625 J

b) so Vnet = v1 + V2 + V3 = sum of k q/r = 9.0E9*(-25.0E-6/0.5 -25.0E-6/0.5 + q/1)=0

q=1.0E-4 C = 100 uC

c) so charge at 0.5 and -0.5 cancel so Fx = 0

d) only one at 1 matters

so F = k q Q/r^2 = 9.0E9*4.0E-6*1.0E-4/1^2= 3.6 N

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