The figure (Figure 1) shows cross sections of five closed surfaces S 1, S 2, etc
ID: 1265910 • Letter: T
Question
The figure (Figure 1) shows cross sections of five closed surfaces S1, S2, etc. Assume that q1 = 6.0?C , q2 = 9.0?C , q3 = 0.90?C , q4 = 7.8?C , q5 = 8.0?C , and q6 = 11.0?C .
Find the net electric flux passing through the surface S1.
Find the net electric flux passing through the surface S2.
Find the net electric flux passing through the surface S3.
Find the net electric flux passing through the surface S4.
Find the net electric flux passing through the surface S5.
All anwers are in terms of Nm^2/C
The figure (Figure 1) shows cross sections of five closed surfaces S1, S2, etc. Assume that q1 = 6.0?C , q2 = 9.0?C , q3 = 0.90?C , q4 = 7.8?C , q5 = 8.0?C , and q6 = 11.0?C . Find the net electric flux passing through the surface S1. Find the net electric flux passing through the surface S2. Find the net electric flux passing through the surface S3. Find the net electric flux passing through the surface S4. Find the net electric flux passing through the surface S5. All anwers are in terms of Nm^2/CExplanation / Answer
Note that
Eflux = qenc / Eo
where
qenc = the total charge enclosed by the surface
Eo = 8.85E-12 C^2/N m^2
Thus, for S1, it encloses not charge. Thus,
Eflux1 = 0 N m^2/C [ANSWER]
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Through surface 2, it encloses q1, q2, and q5. Thus,
qenc = 7.0E-6 C
Thus,
Eflux = qenc / Eo
Eflux2 = 7.91*10^5 N m^2/C [ANSWER, for S2]
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For surface 3, it encloses q2, q3, and q6. Thus,
Eflux = qenc / Eo
Eflux3 = -1.24*10^5 N m^2/C [ANSWER, FOR S3]
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For surface 4, it encloses q5 and q4. Thus,
Eflux = qenc / Eo
Eflux4 = -2.26*10^4 N m^2/C [ANSWER, FOR S4]
********************
For surface 5, it encloses all the given charges. Thus,
Eflux = qenc / Eo
Eflux5 = 5.31*10^5 N m^2/C [ANSWER, FOR S5]
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