The figure ( Figure 1 ) shows three ropes tied together in a knot. One of your f
ID: 2125737 • Letter: T
Question
The figure (Figure 1) shows three ropes tied together in a knot. One of your friends pulls on a rope with 3.0 units of force and another pulls on a second rope with 5.0 units of force.
?A) How hard must you pull on the third rope to keep the knot from moving?
B) In what direction must you pull on the third rope to keep the knot from moving
The figure (Figure 1) shows three ropes tied together in a knot. One of your friends pulls on a rope with 3.0 units of force and another pulls on a second rope with 5.0 units of force. How hard must you pull on the third rope to keep the knot from moving? In what direction must you pull on the third rope to keep the knot from movingExplanation / Answer
Friend 1 = + 3 units at 0 degrees
Friend 2 = 5 units at 120 degrees
Fx = Force you apply in the x-direction
Fy = Force you apply in the y-direction
F = How hard you pull = Magnitude of Force applied
The total forces in the x and y directions must equal 0 if the knot is not allowed to move.
Total Force in the x-direction = 0 = Fx + 3 - cos(60)*5
Solve for Fx = -3 + cos(60)*5 = -0.5 units
Total Force in the y-direction = 0 = Fy + 0 + sin(60)*5
Solve for Fy = -sin(60)*5 = -4.33 units
F = sqrt [ (-0.5)^2 + (-4.33)^2 ] = 4.36 units <-----ANSWER
Draw a vector -0.5 units left. From the arrow draw another vector -4.33 units down. Draw a vector from the origin to the arrow of the 4.33 vector. You should see an angle.
Find the angle by taking the inverse tangent (tan-1)
? = tan-1(0.5 / 4.36) = 6.54
Now, from friend 1 you are 180 degrees + 6.54 degrees anticlockwise from your friend
So, you are 186.54 degrees anticlockwise from Friend 1. <---ANSWER
The final answer is that you are pulling with a force of 4.36 units in a direction 186.54 degrees anticlockwise from Friend 1.<----------ANSWER
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.