A 5.4cm tall object is placed 32cm in front of a spherical mirror. It is desired

Question

A 5.4cm tall object is placed 32cm in front of a spherical mirror. It is desired to produce a virtual image that is upright and 4.3cm tall.

Part A

What type of mirror should be used?

concave

Part B

Where is the image located?

Express your answer using two significant figures.(cm)

Part C

What is the focal length of the mirror?

Express your answer using two significant figures. (cm)

Part D

What is the radius of curvature of the mirror?

Express your answer using two significant figures.

concave

Part B

Where is the image located?

Express your answer using two significant figures.(cm)

Part C

What is the focal length of the mirror?

Express your answer using two significant figures. (cm)

Part D

What is the radius of curvature of the mirror?

Express your answer using two significant figures.

Explanation / Answer

Here ,

ho = 5.4 cm

do = 32 cm

hi = 4.3 cm

A)

as image is smaller than object and it is virtual ,

hence , the mirror is convex.

B)

here , as

hi/ho = -di/do

4.3/5.4 = -di/32

di = -25.5 cm

the image is located at 25 cm behind the mirror

c)

Using mirror formula

1/f = 1/di + 1/do

1/f = 1/(-25.5) + 1/32

solving for f

f = -125.5 cm

f = -130 cm

the focal length is -130 cm

d)

as radius of curvature = 2f

R = 2 * 125.5

R = -250 cm

the radius of curvature is -250 cm

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.