-You inflate your car tires to a gauge pressure of 2.06 atmospheres at a tempera

Question

-You inflate your car tires to a gauge pressure of 2.06 atmospheres at a temperature of 21 oC. After driving a couple of miles the temperature of the tire increases by 32 oC. What is the new gauge pressure to the nearest hundredth of an atmosphere?

-What fraction (to three decimal places) of the air would you have to let out of the tire in the previous problem in order for the pressure to return to its original value?

-What is the average kinetic energy of gas molecules at a temperature of 269 K in units of 10-21 J to two decimal places?

-If the molecules in the previous problem have a mole mass of 46 g, to the nearest m/s what is their rms velocity?

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Explanation / Answer

from pV=nRT we get
p/T = nR/V
right hand side is constant (at first), so
(p/T)?= (p/T)?
2.06atm / (294.15

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