An average force of 250N acts for a time interval of 0.04s on a golf ball (mass

Question

An average force of 250N acts for a time interval of 0.04s on a golf ball (mass 50g)
a. What is the impulse on the golf ball?
b. What is final momentum?
c. What is its final velocity?

2. Collision at 90: Two football players collide at an angle 90 and stick together after the collision. Before the collision, Player A (mass 125kg) had a speed of 4m/s and Player B ( mass 100kg) had a speed of 5m/s. Calculate the total momentum of the players and the final velocity they had after the collision.
(a) ptot -
(b) v1-

3. Dtaw a momentum vector diagram to determine the direction the players had after the collision

4. Calculate the angle a between the direction Player A had before and after the collision!
a is equal to -
(Hint: Use the trigonometric functions tan a is equal to Pa/Pb and a is equal to arctan (tan a) )

View comments (1)

Comments

Still awaiting the detailed solution.

  

An average force of 250N acts for a time interval of 0.04s on a golf ball (mass 50g) a. What is the impulse on the golf ball? b. What is final momentum? c. What is its final velocity? 2. Collision at 90: Two football players collide at an angle 90 and stick together after the collision. Before the collision, Player A (mass 125kg) had a speed of 4m/s and Player B ( mass 100kg) had a speed of 5m/s. Calculate the total momentum of the players and the final velocity they had after the collision. (a) ptot - (b) v1- 3. Dtaw a momentum vector diagram to determine the direction the players had after the collision 4. Calculate the angle a between the direction Player A had before and after the collision! a is equal to - (Hint: Use the trigonometric functions tan a is equal to Pa/Pb and a is equal to arctan (tan a) )

Explanation / Answer

(a)

Impulse produced by the bat is,

I=Ft=(250N)(0.04s)=10kg.m/s

(b)

Impulse is equal to change in the momentum of the ball.

I=mvf-mvi

As the ball initially at rest, the above equation becomes,

I=mvf=10kg.m/s

(c)

vf=I/m=(10kg.m/s)/0.050kg=200m/s

---------------------------------------------------------------------------------------------------------------------------

2.

According to the law of conservation of momentum, the total momentum of the balls before the collision is equal to the total momenntum of the blls after the collision.

total momentum of the balls,

P=m1v1+m2v2=(125kg)(4m/s)+(100kg)(5m/s)=1000kg.m/s

apply law of conservation of momentum.

m1v1+m2v2=(m1+m2)?V

V=m1v1+m2v2/(m1+m2)?=(1000kg.m/s)/(125kg+100kg)=4.44m/s

3. Plot the grapth by representing the Pa on horizontal axis and Pb on vertical axis. Represent the resultant of these two momentums as line drawn from the intersection point of two momentas.

4.

a=tan-1(Pa/Pb)=tan-1((125kg)(4m/s)/(100kg)(5m/s))=450

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.