An automobile whose speed is increasing at a rate of 0.800 m/s 2 travels along a

Question

An automobile whose speed is increasing at a rate of 0.800 m/s2 travels along a circular road of radius 30.0 m.

(a) When the instantaneous speed of the automobile is 2.00 m/s, find the tangential acceleration component.
Magnitude:  
Direction:

in a direction opposite to the automobile's motionin the direction of the automobile's motion    

(b) What is the centripetal acceleration component?
Magnitude:  
Direction:

away from the center of curvaturetoward the center of curvature    

(c) Determine the magnitude and direction of the total acceleration.
Magnitude:  
Direction:  °

inward from the automobile's pathoutward from the automobile's path   

Explanation / Answer

1) tangential accleration = rate of change of speed = 0.8 m/ sec square......2) centripetal accleration = (v)2/ r =4/30 = 0.133m/ sec square . ..

.3) total accleration = square root of (0.8)2 +(0.133)2 = 0.81m/sec square . . .theeta = tan inverse (0.8/0.81) =44.62

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