Deana and Molly have been best friends since childhood. They spend a lot of time

Question

Deana and Molly have been best friends since childhood. They spend a lot of time together. They go shopping sometimes travel together on weekends, and eat out once in a while. Recently, Molly started gaining weight and wondered why her friend, who eats the same dishes when they are out, still keeps her youthful figure Both Deana and Molly are 35 years old. Deana is 5 ft, 4 in tall and weighs 126 lb, and Molly is 5 ft, 7 in tall and weighs 148 lb. Molly has to watch her diet not to gain any more weight. Deana's days are quite busy. She walks her two dogs in the morning and afternoon for almost an hour, goes to power yoga classes twice a week, walks to most of her errands, and plays tennis for two hours on Friday nights. Molly has a desk job and only goes to restorative yoga on Tuesdays and Thursdays. She does only light housework and rarely walks anywhere Compare the EER for both women to see why Molly is having trouble with gaining weight, whereas Deana is not. To calculate EER, use the following equation female EER (kilocalories)-354-(6.91 × age)] + (physical activity factor × [(9.36 × weight in kg) + (726 × height in meters)]) For physical activity factors (referred to as Table 14.3 in the video), use the following table Physical activityPhysical activity Physical activity factor for men 1.00 1.11 1.25 1.45 factor for women 1.00 1.12 1.27 1.48 level sedentary low active active very active Part A - Estimating Daily Energy Requirements for a Healthy Adult What is the daily EER for Deana? Don't forget to convert her weight and height into metric units Round the number of kilocalories to the nearest whole number. During calculations, use numbers rounded to the first decimal place kcal Submit My Answers Give Up

Explanation / Answer

Part A: Deana

Age:35 years

Height :5 ft 4 inch

Coverting to meter, Feet in cm=5 × 30. 48= 152.4 cm[note: to convert feet into cm, feet is multiplied by 30.48, 1 feet is 30.48]

Then multiply the value in inches by 2.54 to get the result of conversion from inches to cm,

4 × 2.54 =10.16cm

Finally add both, 152.4 + 10.16=162.56cm

To convert cm into metre, divide cm by 100

Therefore 1.625meter

So 5ft 4inch=1.625m

Weight= 126lbs = 57 kg

Physical cal activity factor for deana as she is very active female is 1.48.

EER=[354 - (6.91 × 35)] + 1.48 [ (9.36 × 57) +(726 × 1.625)]

=[354-241.85]+1.48×[533.52+1179.75]

=112.15+1.48×[1713.27]

=112.15+2535.6396

=2647.78

=2648

SO EER FOR DEANA IS 2648Kcal

PART B:Molly

Age:35 years

Height:5feet 7inch =1.7m

Weight:148lb=67.1kg=67kg

Phsical activity factor for molly is 1.12as asheis low active.

EER=[354-(6.91×35)]+1.12×[(9.36×67)+(726×1.7)]

=112.5+1.12×[1861.32]

=112.15+2084.7

=2196.85

=2197kcal.

PART C: influence of increase in one grade of physical activity of molly

Physical activity is increased from low active to active =1.27

EER=

354-(6.91×35)]+1.27×[(9.36×67)+(726×1.7)]

=112.5+1.27×[1861.32]

=112.15+2364

=2476.15

=2476kcal.

So there was increase in the EER when the grade of physical activity factor increased, which means, EER is directly proportional to Physical activity factor. When molly was less active her physcal factor was 1.12and EER was 2197Kcal but when she was active her physical activity factor wad 1.27 so her EER was2476kcal , an increase of 279 kcal.

Related Questions

Navigate

• Browse (All)
• Browse D
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.