32. Questions 32-34 refer to the following. X2 + Y,XY rate -k[X:) A reaction and
ID: 1076184 • Letter: 3
Question
32. Questions 32-34 refer to the following. X2 + Y,XY rate -k[X:) A reaction and its experimentally determined rate law are represented above. A chemist proposes. two different possible mechanisms for the reaction, which are given below. Mechanism 1 Mechanism 2 X, — 2x (slow) X3 + 2x (slow) X+Y? XY (fast) X+Y2 + XY +Y (fast) X+XY? -- X,Y: fast) X+XY + X.Y (fast) X,Y + Y + X;Y: (fast) Based on the information above, which of the following is true? (A) Only mechanism I is consistent with the rate law. (B) Only mechanism 2 is consistent with the rate law. (C) Both mechanism I and 2 are consistent with the rate law. (D) Neither mechanism I nor mechanism 2 is consistent with the rate law. AP Chem Eram 2014 MC128 33. The reaction is performed and the instantaneous rate is found to be 6x10* Ms'. Trial X3|| 0.40 0.80 0.80 Y31 0.40 0.40 0.80 Initial Rate (Ms') 6.0x106 Based on the rate law, what would be the predicted initial rate for the reaction in Trial 22 (A) 6.0x106 Ms! (B) 9.0x10° Ms (C) 1.2x105 Ms! (D) 2.4x105 M s!Explanation / Answer
32)
The rate law will be determined by the slowest step in the reaction
Mechanism 1: Slow step: X2------2X(slow)
Hence Rate = k[Reactants] = k[X2]
Mechanism 2: Slow step: X2------2X(slow)
Hence Rate = k[Reactants] = k[X2]
Hence the correct answer must be Option C
Both mechanism 1 and mechanism 2 are consistent with the rate law
Q33)
Rate = k[X2]
6.0 * 10^6 = k[0.40]
k = 1.5 * 10^(-5)
For Trial 2
Rate = k[X2] = 1.5 * 10^(-5) * 0.8 = 1.2 * 10^(-5)
Hence the correct answer is Option C
Q34)
Rate = k[X2]
6.0 * 10^6 = k[0.40]
k = 1.5 * 10^(-5)
For Trial 3
Rate = k[X2] = 1.5 * 10^(-5) * 0.8 = 1.2 * 10^(-5)
Hence the correct answer is Option C
Related Questions
drjack9650@gmail.com
Navigate
Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.