The electro winning point in your copper operation uses an average of 2.5 V DC p

Question

The electro winning point in your copper operation uses an average of 2.5 V DC potential across a 40-cathode electrolytic cell (each cathode is trio-faced & 1 m^2 in area) Amperage through the unit is 40,000 ft a) What is the current density of the catholic reaction? b) How much Cu will you produce per 7 day period if you have 95% current efficiency? c) How much energy is consumed per kg of copper produced? d) How much copper does your operation produced per year if you have 250 of these cells?

Explanation / Answer

a) total current = 40000A

Cells= 40*2=80

Area=1 m2

J=I/A=(40000)/(40*2*1)=500 A/m2

Related Questions

Navigate

• Browse (All)
• Browse T
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.