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What is the expression for K_c for the following equilibrium? CaCO_3(s) righthar

ID: 1066712 • Letter: W

Question

What is the expression for K_c for the following equilibrium? CaCO_3(s) rightharpoonleftharpoon CaO(s) + CO_2(g) [CO2] [CaCO_3]/[CaO][CO_2] [CaO][CO_2]/[CaCO_3] [CaO][CO_2] 1/[CO_2] In which of the following solvents would you expect KBr to be most soluble? CCI_4 (carbon tetrachloride) CH_3CH_2OH (ethanol) C_6H_14 (hexane) C_6H_12 (cyclohexane) C_6H_6 (benzene) Which of the following molecules is polar? SF_6 CO_2 BF_3 CCl_4 NO_2 Which of the following aqueous solutions has the highest osmotic pressure at 25 degree C (assume 100% dissociation for all soluble ionic compounds)? 0.15m K_3PO_4 0.30m NH_4NO_3 0.20m KI 0.45m C_12H_22O_11 0.25m K_2CO_3 Consider the following equilibrium: PCl_3(g) + Cl_2(g) rightharpoonoverleftharpoon PCI_5(g); delta H = - 92 kJ The concentration of PCl_3 at equilibrium may be increasing by decreasing the temperature. the adding Cl_2 to the system. the addition of neon. the addition of PCI_5. increasing the pressure. A titration of an acid and base to the equivalence point results in a noticeably ac solution. It is likely this titration involves a weak acid and a weak base (where K_a equals K_b). a strong acid and a strong base. a strong acid and a weak base. a weak acid and a strong base. Given the rate law. Rate = k[A][B], what are appropriate units for the rate cons s^-1 M^-1s^-1 M^-2s^-1 M/s M^2/s

Explanation / Answer

15. CaCO3(s) ---------> CaO (s) + CO2(g)

    KC = [CO2]   for solids [CaCO3] =1, [CaO] = 1

A. [CO2]

16. KBr is ionic compound . It is soluble in polar solvent. It is soluble in ethanol

   D. CH3CH2OH

17. E. NO2

       NO2 is polar molecule .It is bent shape.

18. K3PO4 is contains 4 ions . So number of particles are increases.osmotic pressure is more.

    A. 0.15mK3PO4

19. E the addition of PCl5

conc of products are increases. The equilibrium shift to left side.

20. C strong acid and weak base

21. Rate = K[A][B]

it is second order . The units of second order is M-1 sec-1

B. M-1 sec-1

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