perature after mixing mL Heat Released Moles of NaOH (s) dissolved Enthalpy of s

Question

perature after mixing mL Heat Released Moles of NaOH (s) dissolved Enthalpy of solution per mole of NaOH (s), AHi 5.00 moles kJ/mole Reaction 2 Mass of NaOH (s) (1XX, XX-last 2 digits of ID#) volume of 1.0 M HCl measured (4X.0, X is the last digit of ID #) Initial temperature of 1.0 M HCI Temperature after mixing Heat Released Moles of NaOH (s) used Moles of HCI used Moles of acid Neutralized Enthalpy of Neutralization, AH2 mL ,ISL °c 635moles moles kJ/mole mL mL oC OC eaction3 40.0 olume of 1.0 M HCI measured f 1 0 M NaOH (4X.ON is the last digit of ID#)

Explanation / Answer

Your question is not proper. I assume your question is "How can you solve for moles of acid neutralized? And the net balanced reaction of neautralization? "

The answer is :

The number of moles of acid nuetralized can be calculated from the balanced reaction for neutralization.

This is the reaction between NaOH(base) and HCl (acid) and forms salt (NaCl) and water,

The balanced reaction is

NaOH + HCl ----> NaCl + H2O

one mole of NaOH react with one mole of HCl in the above reaction.

So, 0.035 moles of NaOH react with 0.035 moles of HCl .

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