A three step process begins with an inital 27 states going to 14 states (step 1)

Question

A three step process begins with an inital 27 states going to 14 states (step 1) which goes to 56 states (Step 2) and Completes with 36 states (Step 3). What best describes the molar entropy change of this process? correct answer not listed non-spontaneous, DeltaS = R In (14/27) spontaneous, DeltaS = R ln (36 - 27) non-spontaneous, DeltaS = R In (14 - 27) spontaneous, DeltaS = R In (36/27) If DeltaS_uni = 1357 j/mol middot K, what is DeltaG_sys at 426K? Report in kJ/mol Numerical answer Do not use scientific notation!

Explanation / Answer

Question1:
S = R ln (36 / 27) [final state / initial/state]
this equation best describes the molar entropy of the process.
entropy will have negative value and hence spontaneous

Question 2:
Gsys = - TSuniv  = - 426 K * 1357 J / mol K = -578082 J/mol = -578.082 kJ / mol

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