If a gas at STP occupies 3.36 L, how many moles does it contain? 0.15 0.81 3.4 6

Question

If a gas at STP occupies 3.36 L, how many moles does it contain? 0.15 0.81 3.4 6.7 What is the volume of 2.00 mol of helium gas at 27 degree C and 3.00 6.1 times 10^-2 L 1.48 L 16.4 L 44.8 L If 6.60 g of a gaseous compound occupy a volume of 1.20 L at 27 degree C and 0.967 atm, the molar mass of the compo 109 g middot mol^-1 123 g middot mol^-1 140 g middot mol^-1 165 g middot mol^-1 The ideal gas law best describes the behavior of water vapor at 373 K and 1 atm. 473 K and 1 atm. 473 K and 10 atm. 0 K and 1 atm.

Explanation / Answer

11]

1 mole of gas occupies 22.4 Litres at STP

3.36 L was occupied by = 1*3.36 / 22.4 = 0.15 moles

12]

PV = nRT

3*V = 2*0.0821*[27+273]

V = 16.4 L

13]

PV = nRT

0.967*1.2 = n*0.0821*300

n = 0.04711

n = mass /Molar mass

Molar mass = 140 g/mol

14] B

473 K and 1 atm

Related Questions

Navigate

• Browse (All)
• Browse I
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.