If a gambler places a bet on the number 7 in roulette, he or she has a 1/38 prob

Question

If a gambler places a bet on the number 7 in roulette, he or she has a 1/38 probability of winning a. Find the mean and standard deviation for the number of wins of gamblers who bet on the number 7 two hundred and seventy times b. Would O wins in two hundred and seventy bets be an unusually low number of wins? a.The value of the mean is -O (Round to one decimal place as needed ) The value of the standard deviation is = (Round to one deamal place as needed ) b. Would 0 wins in 270 bets be an unusually low number of wins? o A. Yes, because o is within the range of usual values O B. No, because 0 is within the range of usual values O C. Yes, because 0 is below the minimum usual value 0 D. Yes, because 0 is greater than the maximum usual value

Explanation / Answer

a) Mean = n*p = 270*(1/36) = 7.5

sigma = sqrt(n*p*(1-p)) = sqrt(270*(1/36)*(35/36)) = 2.7

b) Option C, Yes because 0 is below the minimum usual value

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