If a gas at STP occupies 3.36 L, how many moles does it contain? 0.15 0.81 3.4 6

Question

If a gas at STP occupies 3.36 L, how many moles does it contain? 0.15 0.81 3.4 6.7 What is the volume of 2.00 mol of helium gas at 27 degree C and 3.00 atm? 6.1 times 10^-2 L 1.48 L 16.4 L 44.8 L If 6.60 g of a gaseous compound occupy a volume of 1.20 L at 27 degree C and 0.967 atm, the molar mass of the compound is 109 g middot mol^-1 123 g middot mol^-1 140 g middot mol^-1 165 g middot mol^-1 The ideal gas law best describes the behavior of water vapor at 373 K and 1 atm. 473 K and 1 atm. 473 K and 10 atm. 0 K and 1 atm. The mass of 560 cm^3 (STP) of an unknown gas is 1.60 g. This gas could be oxygen. carbon dioxide. (D) chlorine. sulfur dioxide. How many grams of CO_2 would occupy an 8.8 L flask at 300 K and 1.1 atm? 14g 17g 22g 32 g

Explanation / Answer

11)
1 mol of gas at STP occupies 22.4 L

so,
moles of gas = volume / 22.4
= 3.36/22.4
= 0.15 mol

Answer: A

12)
n = 2.00 mol
V= ?
P = 3.00 atm
T = 27 oC = (27+273.15) K =300.15 K

use:
P*V = n*R*T
3*V = 2*0.0821*300.15
V = 16.4 L

Answer: C

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