Print calculator Periodic Table uestion 12 of 16 Sapling Learning this question

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Print calculator Periodic Table uestion 12 of 16 Sapling Learning this question has bem astomized by the faculty at University of Arizona Uric acid dissociates as shown in the figure at the right with a pKa of 5.80, and can be treated HN as a simple monoprotic acid in this pH range. Its solubility in urine depends on the relative amount of protonated and un forms. Aurine sample was found to have a pH of 4.91 HA A H What would be the ratio of the unprotonated form, A to the protonated form, HA for uric acid in this urine sample? 0.72 HA There is additional feedback View this feedback bar again to hide the additional feedback. Previous Give up view solution a Try Again ONext aExt 15) dmg Flash Player (14) dmg Flashplayer 13) dmg

Explanation / Answer

When uric acid is dissociating as

HA <-----> A- + H+

in solution it behaves as a buffer.

Thus its pH is given by Hendersen equation as

pH = pKa + log [A-] /[HA]

Given ph = 4.91 and pKa = 5.8

thus log [A-] /[HA] = pH - pKa = 4.91-5.8 =- 0.89

and the ratio [A-] /[HA] = 0.1288

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