An insulated container is used to hold 40.60 g of water at 38.60 degree C. A sam

Question

An insulated container is used to hold 40.60 g of water at 38.60 degree C. A sample of copper weighing 8.30 g is placed in a dry test tube and heated for 30 minutes in a boiling water bath at 100.10 degree C. The heated test tube is carefully removed from the water bath with laboratory tongs and inclined so that the copper slides into the water in the insulated container. Given that the specific heat of solid copper is 0.385 J/(g- degree C), calculate the maximum temperature of the water in the insulated container after the copper metal is added.

Explanation / Answer

Heat lost by the copper = Heat gained by the water

m C dT copper = m C dT water


(8.30 g) ( 0.385 J/g*degreesC) (dT cu) = (40.60 g) (4.184 J/g*degreesC) (dT h2o)

(3.1955) (dT cu) = (169.87) (dT h2o)

(3.1955) (100.10 - Tf) = (169.87) (Tf - 38.6)

319.86 - 3.1955 Tf = 169.87 Tf - 6556.982

6876.842 = 173.0655 Tf

Tf = 39.7354 C

Answer is rounded to
39.7 Celsius

Related Questions

Navigate

• Browse (All)
• Browse A
• Subjects

---

---

Integrity-first tutoring: explanations and feedback only — we do not complete graded work. Learn more.