An insulated container is used to hold 40.60g of water 33.70 degrees Celsius. A

Question

An insulated container is used to hold 40.60g of water 33.70 degrees Celsius. A sample of copper weighing 7.50g is placed in a dry tube and heated for 30 minutes in a boiling water bath at 100.10 degrees. The heated test tube is carefully removed from the water bath with laboratory tongs and inclined so that the copper slides into the water in the insulated container. Given that the specific heat of solid copper metal is 0.385J/(g.C), calculate the maximum temperature of the water in the insulated container after the copper metal is added. An insulated container is used to hold 40.60g of water 33.70 degrees Celsius. A sample of copper weighing 7.50g is placed in a dry tube and heated for 30 minutes in a boiling water bath at 100.10 degrees. The heated test tube is carefully removed from the water bath with laboratory tongs and inclined so that the copper slides into the water in the insulated container. Given that the specific heat of solid copper metal is 0.385J/(g.C), calculate the maximum temperature of the water in the insulated container after the copper metal is added.

Explanation / Answer

Since

heat lost( by copper) = heat gained(by water)

Q1 = Q2

m1c1dT1 = m2c2dT2

7.5 g * 0.385 J/g.C * ( 100.1 - Tf) = 40.6 g * 4.184 J/g.C * ( Tf - 33.7) C

289.04 - 2.8875 Tf = 169.87 Tf - 5724.63

5724.63 + 289.04 = (169.87 + 2.8875) Tf

6013.67 = 172.76 Tf

Tf = 34.809 C

Maximum temperature of water = 34.809 C

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