An aqueous solution of hydioiodic acid is standardized by titration with a 0.156

Question

An aqueous solution of hydioiodic acid is standardized by titration with a 0.156 M solution of sodium hydroxide. If 12.5 mL of base are required to neutralize 28.0 mL of the acid, what is the molarity of the hydioiodic acid solution? (ANSWER IN) M hydroiodic acid An aqueous solution of barium hydroxide is standardized by titration with a 0.134 M solution of nitric acid. If 15.9 mL of base are required to neutralize 19.4 mL of the acid, what is the molarity of the barium hydroxide solution? (ANSWER IN) M barium hydroxide An aqueous solution of calcium hydroxide is standardized by titration with a 0.200 M solution ofhydrochloric acid. If 25.7 ml of bate are required to neutralize 25.2 mL of the acid, what is the molarity of the calcium hydroxide solution? (ANSWER IN) M calcium hydroxide For the following reaction, 0.568 moles of sodium chloride are mixed with 0.585 moles of silver nitrate. sodium chloride (aq) + silver nitrate (aq) silver chloride (s) + sodium nitrate (aq) What is the FORMULA for the limiting reagent? What is the maximum amount of silver chloride that can he produced? moles For the following reaction, 0.203 moles of nitrogen gas are mixed with 0.486 moles of oxygen gas. Nitrogen (g) + oxygen (g) nitrogen monoxide (g) What is the FORMULA for the limiting reagent?

Explanation / Answer

6)milli equivalents of acid = milliequivalents of base

28xN = 12.5x 0.156 ( both acid and base are monoacidic and monobasic)

molarity of acid = 0.0696M

7) meq of acid = 0.134 x 19.4

meq of base = 15.9 x 2 x M ( diacidic base)

Thus M = 0.0817 M

Q8) Calcium hydroxide is also a diacidic base

Thus 0.2 x 25.2 = 25.7 x 2 x M

Hence M = 0.09805 M

Q9) NaCl (aq) + AgNO3 (aq) ------> AgCl(s) + NaNO3(aq)

According to balanced equation

1 mole of NaCl reacts with 1 mole of AgNO3

Given 0.568 moles of NaCl treated with 0.585 moles of AgNO3

Thus moles of Na Cl are less than moles of AgNO3 and hence Na Cl is the liming agent.( the one consumed completely in the reaction).

1 mole of NaCl reacts with 1 moles of AgNO3 to give 1 moles of AgCl

Hence the moles of AgCl formed = moles of NaCl consumed = 0.568 moles

Q10) The reaction is

N2(g) + O2(g) --------> 2NO(g)

That is 1 mole of N2 reacts with 1 moles of O2

Given 0.203 moles of N2 reacts with 0.486 moles of O2

implies N2 is the liming agent and is reacted completely to give product.

!mole of N2 gives 2 moles of NO

Thus 0.203 moles of N2 reacts with 0.203 moles of O2 to give 0. 406 moles of NO.

  

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