Experiment 7 CHM 112 Name Pre-Laboratory Assignment 1. o mu of M NaoH are dilute

Question

Experiment 7 CHM 112 Name Pre-Laboratory Assignment 1. o mu of M NaoH are diluted with water to avolume of 40o mL Determine the molarity of the resulting solution. a. How many moles of NaoH there are in 7.0 mLof3.0M NaoH? Hint: Use Eq. 1 and make sure the volume is in liters. moles b. The total number of moles ofNaoH is notchanged on dilution. The molarity after dilution can therefore be found by Eq. using the final volume of the solution. Calculate that molarity. 2. In an acid-base titration, 25.62 mu of an NaoH solution are needed to neutralize 26.23 mLof a 0.1036 M HCI solution. Use these steps to find the molarity of the NaoH. a. First note the value of M n the HCI solution. b. Find M in the NaoH solution. (use Eq. 3.) c, obtain MNaoH from M OH".

Explanation / Answer

1. Initial molarity of NaOH = 3.0 M

Initial Volume of NaOH = 7.0 mL

Final Volume of NaOH solution = 400.0 mL

Let final molarity be M2.

Using, M1V1 = M2V2

3.0 * 7.0 = M2 * 400.0

M2 = 21.0 / 400.0

M2 = 0.0525 M

(a). We know that,

Moles = Molarity * Volume (L)

= 3.0 * 0.007

= 0.021 moles

(b). Volume after dilution = 400 mL = 0.4 L

Molarity = Moles / Volume (L)

= 0.021 / 0.4

= 0.0525 M

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