Experiment 32 epr She Galvanic Cells, the Nernst Equot quati Desk No. Date Lab S

Question

Experiment 32 epr She Galvanic Cells, the Nernst Equot quati Desk No. Date Lab Sec Name A. Reduction Potentials of Several Redos Couples galvanke cells Fill in the following table with your osservations and interpretations from the Galvanie| E Cell Measured Anode t Equation for Anode Reaction Equation for Cathode Reaction Cathode @g-2n 1-Cto4 @cu- Zn |.cde4. Zn Zalnu t 2e--|-ae(auree. cu 2t 2 2n-Mg t 2. 2 1. Write balanced equations for the six cell reactions. 2. What is the oxidizing agent in the Zn-Mg cell? 3. Compare the sum of the Cu-Zn and Za-Mg cell potentials with the Cu-Mg cell potential. Explain. 4. Compare the sam of the Zn-Fe and Zn-Mg cell potentials with the Fe-Mg cell potential. Explain. Experiment 32 359 164

Explanation / Answer

1. Balanced equations

Cu-Zn : Cu2+(aq) + Zn(s) ---> Cu(s) + Zn2+(aq)

Cu-Mg : Cu2+(aq) + Mg(s) ---> Cu(s) + Mg2+(aq)

Cu-Fe : Cu2+(aq) + Fe(s) ---> Cu(s) + Fe2+(aq)

Zn-Mg : Zn2+(aq) + Mg(s) ---> Zn(s) + Mg2+(aq)

Fe-Mg : Fe2+(aq) + Mg(s) ---> Fe(s) + Mg2+(aq)

Zn-Fe : Fe2+(aq) + Zn(s) ---> Fe(s) + Zn2+(aq)

2. Oxidizing agent in Zn-Mg cell is Zn2+

3. Eo for Cu-Zn = 0.34 - (-0.76) = 1.10 V

Eo for Zn-Mg = -0.76 - (-2.37) = 1.61 V

Sum of Cu-Zn and Zn-Mg = 2.71 V

Eo for Cu-Mg = 0.34 - (-2.37) = 2.71 V

Thus, the sum of Cu-Zn and Zn-Mg potential equals the Cu-Mg potential.

4. Eo for Zn-Fe = -0.44 - (-0.76) = 0.32 V

Eo for Zn-Mg = -0.76 - (-2.37) = 1.61 V

Sum of Zn-Fe and Zn-Mg = 1.93 V

Eo for Fe-Mg = -0.44 - (-2.37) = 1.93 V

Thus, the sum of Zn-Fe and Zn-Mg potential equals the Fe-Mg potential.

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