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Machel Mcleoc X a Secure htps/www awhalcks.com/alekscgi/islewel'1o u 1gNslk 7993)H ogoill chwiCeBZbuhuBYTIONc7m/D3ZccTUDE/B3i'T3n0002dUPLTwZEklpwtALYk 1G OPPESXeqlla STOICHIOMETRY Limiting reactants Mitcha uquid hexane (CHCHCH, will react with gaseous oxygen (o,) to produce gaseou s carbon dioxide (CO) and gaseous water (H,O). Suppose 19.8 g of hexane is mixed with 31. g of oxygen. Calculate the minimum mass of hexane that could be left over by the chemical correct number of significant digits. ls Explanat n Check O Type here to search

Explanation / Answer

C6H12 (l) +   9 O2 (g)    ---------------> 6 CO2 (g) + 6 H2O (g)

84.16 g           288 g

19.8 g              31 g

84.16 g C6H12   -------------> 288 g O2

19.8 g C6H12    ------------->   ??

mass of O2 needed = 19.8 x 288 / 84.16

                                = 67.76 g

so here limiting reagent is O2.

excess hexane left over = 19.8 - (84.16 x 31 / 288)

excess hexane left over   = 10.7 g

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