n A 0857 mol sample of O2 gas is at STP. What volume does the gas occupy A) 26.1

Question

n A 0857 mol sample of O2 gas is at STP. What volume does the gas occupy A) 26.1 mol L B)0.0268 mol ? C)21.1 mol D) 19.2 mol E) 1.22 mol 8) 1.25 mol of 2.89 mol of nitrogen gas, an 8) A mixture of gases contains 3,21 mol ofoxygen gas, 2.89 mol of nitrogen gas, chlorine gas. The total pressure of the gasses is 5.00 atm. What is B) 16.1 atm D) 7.35 atm 8) A mixhure of gases the mixture? A) 1.56 atm C)2.18 atm 9) ressure of 1.4 atm. 9) In a mixture, hydrogen gas has partial pressure of 1.2 atm, oxygen has a partial p total and nitrogen has a partial pressure of 0.80 atm. The rest of the mixture is water vapor pressure is 6.0 atm. What is the partial pressure due to water vapor? A) 9.4 atm C)4.5 atm B) 6.0 atm D) 2.6 atm 10) A 0.465 g sample of an unknown compound occupies 245 ml. at 298 K and 1.22 atm. What is the 10)_ molar mass of the unknown compound? A) 26.3 g/mol B) 81.8 g/mol C) 12.2 g/mo D) 380 g/mol E) 33.9 g/mol 11) Determine the volume of H25 (at 375 K and 1.20 atm) needed to produce 55.0 g of S. Assume that 11) there is excess S02 present 2 H2S(g)+S02) 3S)+2 H20(g) A) 66.0 L B) 29.3 L C) 44.0 L D) 341L E) 22.7L Which statement best explains the meaning of the phrase "ike dissolves like"? A) A solvent and solute with similar elemental composition will readily form a solution. B) A solvent will easily dissolve a solute of similar molar mass. C A solvent and solute with similar intermolecular forces will readily form a solution. D) The only true solutions are formed when water dissolves non-polar solutes. E) None of these statements is correct.

Explanation / Answer

7) with moles O2 = 0.857 mol

Volume occupied = 0.857 mol x 22.4 L = 19.2 L

D) 19.2 L

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8) Partial pressure of O2 = [3.21/(3.21 + 2.89 + 1.25)] x 5 atm = 2.18 atm

C) 2.18 atm

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9) Partial pressure of water = 6 - (1.2 + 1.4 + 0.8) = 2.6 atm

D) 2.6 atm

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10) molar mass = 0.465 x 0.08206 x 298/1.22

                          = 38.0 g/mol

D) 38.0 g/mol

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11) Volume H2S needed = (55/32) x 375 x 0.08206/1.20

                                         = 44.0 L

C) 44.0 L

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12) True statement about like-dissolves-like,

C)

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