NH2 HO Congratulations, you were just hired as a pharmacy tech! The first order
ID: 104204 • Letter: N
Question
NH2 HO Congratulations, you were just hired as a pharmacy tech! The first order you get is for 45 mg/kg of Augmentin (a penicillin antibiotic) to be taken every 12 hours by the patient. The patient (a young child) weighs 39 lbs. As the pharmacy tech you decide to prepare 300.0 mL of arn Augmentin solution containing 125 mg Augmentin/5.00 mL of solution. The only measuring device you can find for the parents is a syringe that measures in cubic millimeters. How many cubic millimeters will you tell the child's parents to give him every twelve hours? If the only measuring device you had was in fluid ounces, how many would they give? If the only measuring device you had was in cubic inches, how many would they give? If the prescription states to take all of the Augmentin, how many days will the child have to take the antibiotic?Explanation / Answer
We know that 1 kg = 2.20462 lb; therefore, weight of the child in kgs = (39 lb)*(1 kg/2.20462 lb) = 17.690 kg.
Weight of Augmentin required by the child every 12 hours = (45 mg/kg)*(17.690 kg) = 796.05 mg.
5.00 mL of the Augmentin solution contains 125 mg; therefore, milliliters of the solution required by the child every 12 hours = (796.05 mg)*(5.00 mL)/(125 mg) = 31.842 mL 31.84 mL (ans).
We know that 1 fluid ounce = 29.5735 mL; therefore, number of fluid ounces of the Augmentin solution required by the child = (31.842 mL)*(1 fluid ounce/29.5735 mL) = 1.07670 fluid ounce 1.08 fluid ounce (ans).
Again, we have 1 cu in = 16.3871 mL; therefore, number of cubic inches required by the child = (31.842 mL)*(1 cu in/16.3871 mL) = 1.9431 cu in 1.94 cu. in (ans).
Weight of Augmentin contained in 300.0 mL of a 125 mg/5.00 mL solution = (300.0 mL)*(125 mg/5.00 mL) = 7500 mg.
The child requires 796.05 mg Augmentin per 12 hours; therefore, the time required by the child to consume 7500 mg Augmentin = (7500 mg)*(12 h)/(796.05 mg) = 113.058225 h = (113.05822 h)*(1 day/24 h) = 4.7107 days 4.71 days = 4d17h4min (ans).
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